X^2+25x-625=0

Solution for X^2+25x-625=0 equation:

X^2+25X-625=0

a = 1; b = 25; c = -625;
Δ = b2-4ac
Δ = 252-4·1·(-625)
Δ = 3125
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3125}=\sqrt{625*5}=\sqrt{625}*\sqrt{5}=25\sqrt{5}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-25\sqrt{5}}{2*1}=\frac{-25-25\sqrt{5}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+25\sqrt{5}}{2*1}=\frac{-25+25\sqrt{5}}{2}
$